How to handle asynchronous For loop in JavaScript

How to handle asynchronous For Loop in Js

Since JavaScript is a single-threaded programming environment, some times it gives confusing outputs when time-consuming processes are executed middle of a code block. Using Asynchronous JavaScript such as async, await and promises developers can overcome the occurrence of those confusing outputs.

From today’s article, I am going to talk about how an asynchronous for loop can be handle in JavaScript.

Before moving further it would be better to have mentioned that I am not going to explain basic concepts of async,await and promises in JavaScript. I am going to explain only about handling asynchronous for loop.

Example time-consuming function

I have created a time-consuming function to show how it works with different for loops.

const waitFunc = () => {
 return new Promise(res => setTimeout(res, 5000));
}
const asyncDemoFunction = async (str) => {
 await waitFunc();
 console.log(str);
}

Is forEach() wait for results?

Test using an asynchronous function.

var demoList = ['a','b','c'];
const waitFunc = () => {
 return new Promise(res => setTimeout(res, 5000));
}
const asyncDemoFunction = async (str) => {
 await waitFunc();
 console.log(str);
}
//forEach example
const forEachWithAsync = (demolst) => {
  demolst.forEach(async (i) =>{ 
    await asyncDemoFunction(i);
  });
  console.log("done");
}
forEachWithAsync(demoList);

results:

done
a
b
c

From this example, we can clearly see forEach(), not giving the expected results and not waiting until the finishing of execution of the time-consuming function.

Q: How to write For Loop to wait for results?

a: using thefor loop in an asynchronous function. 😀

let’s see an example of how to do it

var demoList = ['a','b','c'];
const waitFunc = () => {
 return new Promise(res => setTimeout(res, 5000));
}
const asyncDemoFunction = async (str) => {
 await waitFunc();
 console.log(str);
}
//for loop example
const asyncForLoop = async (strList) => {
 for (const str of strList) {
 await asyncDemoFunction(str);
 }
 console.log("done");
}
asyncForLoop(demoList);

result:

a
b
c
done

for loop gave the expected answer and waited until the finishing of execution of the time-consuming function.

Thank you Shenal Theekshana for helping me in writing a better article by proofreading.

don’t hesitate to share any comment with me.